Standard printer paper has a thickness of 0.1mm. write an equation for a function that should approximately the thickness of a sheet of paper after nn folds. f(n)=f(n)=

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Folding a paper will make it thickness become double from it before.
Unfolded paper has 1 thickness
1 times folded paper has 2 thickness
2 times folded paper has 4 thickness
3 times folded paper has 8 thickness

From here it is clear that the pattern is [tex] 2^{n} [/tex]. SInce the paper is 0.1mm, then the function would be:
f(n)= [tex] 2^{n} [/tex] x 0.1mm
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