Question

What property was used on 14k+2(3k+5)-5=10 to obtain 14k+6k+10-5=10

Answer 1

The difference between

i) 14k+2(3k+5)-5=10  and

ii)  14k+6k+10-5=10

is the equality 2(3k+5)=6k+10


The property used here, can be described for any numbers a, b and c as:

$a \cdot (b+c)=a \cdot b +a \cdot c$


This is called the DISTRIBUTIVE PROPERTY 


Answer: DISTRIBUTIVE PROPERTY