Question

Select the statements that are true for the graph of y=(x+2)^2+4

The vertex is (2, 4) .
The graph has a minimum.
The vertex is ​ (−2, 4) ​.
The graph has a maximum.

Answer 1

alrigty

in form
$y=a(x-h)^2+k$
the vertex is (h,k)
the constant, a, deterimines the size and direction
if a>0, then the parabola opens up and the vertex is the minimum
if a<0 then the parabola opens down and the vertex is the maximum

so we are given
$y=1(x-(-2))^2+4$
1>0 so it opens up
vertex is (-2,4)
the vertex is a minimum


the vertex is (-2,4) and the graph has a minimum

Answer 2

The answers are b) The graph has a minimum and c) the vertex is (-2,4). I just took the test it is correct!

Hope this helped you! :3