Answer:
[tex]\log_8(64) = 2[/tex]
Step-by-step explanation:
We are given an equation:
[tex]8^2 = 64[/tex]
We have to convert this into a logarithmic equation.
We know that:
[tex]b^x = a[/tex]
where b is the base and x is the exponent.
Then, it can be written as:
[tex]\log_b(a) = x[/tex]
So, we have b = 8, x = 2 and a = 64
Thus, we can write:
[tex]\bold{\log_8(64) = 2}[/tex]
It is the required logarithmic equation.