For this problem, we use the derived equations for rectilinear motion at constant acceleration.
a = (v - v₀)/t
x = v₀t + 0.5t²
where
a is acceleration
v₀ and v are the initial and final velocities, respectively
x is the distance
t is the time
The solution is as follows:
a = (29 m/s - 0 m/s)/8.20 s = 3.54 m/s²
Using this to the second equation:
x = (0 m/s)(8.20 s) + 0.5(3.54 m/s²)(8.20 s)²
x = 119 m
