Write the point-slope form of the line that passes through (1, -5) and is parallel to a line with a slope of 1. Include all of your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Respuesta :

y - y1 = m(x - x1)
slope(m) = 1...because a parallel line will have the same slope
(1,-5)...x1 = 1 and y1 = -5
now we sub
y - (-5) = 1(x - 1) =
y + 5 = 1(x - 1) <== u could leave that first " one " out if u want...

Answer:

[tex]y+5=1(x-1)[/tex]

Step-by-step explanation:

The point-slope form of a line is:

[tex]y-y_{1}=m(x-x_{1})[/tex]; where [tex]y_{1}[/tex] and [tex]x_{1}[/tex] are the coordinates of a given point, and m is the slope.

In addition, when two line are parallel means that they both have the same slope. So, the point-slope form we have to find it's gonna have [tex]m=1[/tex], because is parallel to a line with that slope. Also, the given point is [tex](1;-5)[/tex].

Now, we just replace all values and isolate [tex]y[/tex]:

[tex]y_{2}-y=m(x_{2}-x)\\y-(-5)=1(x-1)\\y+5=1x-1\\y=1x-1-5\\y=x-6[/tex]

Therefore, the equation of the parallel line is:

[tex]y=x-6[/tex]

And the point-slope form is:

[tex]y+5=1(x-1)[/tex]

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