emukas
emukas
29-08-2017
Mathematics
contestada
I need to solve question 3
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mreijepatmat
mreijepatmat
29-08-2017
3) 3.sec² Ф = 4.tan² Ф
but sec² Ф = 1/cos² Ф
3/cos² Ф = 4.tan² Ф
3/4 = (tan² Ф).(cos² Ф) ; tan² Ф = sin² Ф/cos² Ф
3/4 = (sin² Ф)x(cos² Ф)/(cos² Ф)
sin² Ф = 3/4
a) sin Ф = +(√3)/2 and b) sin Ф = - (√3)/2
sin Ф = + - (√3)/2 → Ф =π/3 + kπ/3
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