Select the graph and the description of the end behavior of f(x) = −x3 − 2.




Answer: Option 4 is correct
Explanation:
End behaviour of graph can be check by following rules
Case 1: even degree and positive leading coefficient
[tex]x\rightarrow -\infty[/tex] [tex]f(x)\rightarrow \infty[/tex]
[tex]x\rightarrow \infty[/tex] [tex]f(x)\rightarrow \infty[/tex]
Case2: Even degree and negative leading coefficient
[tex]x\rightarrow -\infty[/tex] [tex]f(x)\rightarrow -\infty[/tex]
[tex]x\rightarrow \infty[/tex] [tex]f(x)\rightarrow -\infty[/tex]
Case 3: odd degree and positive leading coefficient
[tex]x\rightarrow -\infty[/tex] [tex]f(x)\rightarrow -\infty[/tex]
[tex]x\rightarrow \infty[/tex] [tex]f(x)\rightarrow \infty[/tex]
Case4: Odd degree and negative leading coefficient
[tex]x\rightarrow -\infty[/tex] [tex]f(x)\rightarrow \infty[/tex]
[tex]x\rightarrow \infty[/tex] [tex]f(x)\rightarrow -\infty[/tex]
Here we have a case of odd degree and negative leading coefficient here when [tex]x\rightarrow -\infty[/tex] [tex]f(x)\rightarrow \infty[/tex]
[tex]x\rightarrow \infty[/tex] [tex]f(x)\rightarrow -\infty[/tex]
Hence, Option 4 is correct