Question

A circuit node has current ia entering and currents ib and ic exiting, where it is known that ia=5 ma and ib=9 ma. what is current ic?

Answer 1

The current is the flow of electrons. It is expressed as Coulombs per second, or Amperes. Since it is a flow, all that comes in must go out. The basis here is the node. Since ia is the full flow, it must be greater than ib or ic. So, I think the given information is wrong. It should be ia = 9 mA and ib=5 mA.

Current entering = Current leaving
ia = ib + ic
9 mA = 5 mA + ic
ic = 9 mA - 5 mA = 4 mA 

Answer 2

The value of current ic, for the circuit node, where the current is entering and exiting, is 4 ma.

What is Kirchhoff law for current of node?

Kirchhoff law for a circuit note says that, the sum of all the current enter at a node and leave from a circuit node is equal to the zero.

Kirchhoff law for a circuit note can also be stated as, the amount of all the current entering at a note of a circuit is equal to the amount of current leaving to that node.

The circuit node has current ia entering and currents ib and ic exiting, The values of the current is given as,

$i_a=5 \rm mA$

$i_b=9 \rm mA$

The the amount of all the current entering at a note of a circuit is equal to the amount of current leaving to that node. As, the circuit node has current ia entering and currents ib and ic exiting. Therefore,

$i_a=i_b+i_c\\9=5+i_c\\i_c=9-5\\i_c=4 \rm mA$

Thus the value of current ic, for the circuit node, where the current is entering and exiting, is 4 ma.

Learn more about the Kirchhoff law here;

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