If a square-shaped pool with side lengths are 3a^5 then find the area of the pool
solution:
A = (3a^5) x (3a^5)
= 9a^5+5
= 9a^10
The area of the square-shaped pool are 9a^10 based on the given side length which is 3a^5
Answer:
Area of the pool is [tex]9a^{10}[/tex].
Step-by-step explanation:
If my neighbor has a pool in square shape with the side lengths = [tex]3a^{5}[/tex]
We know area of a square is represented by
Area = (side)²
By putting measure of side in the given formula,
Area = [tex](3a^{5}\times 3a^{5})[/tex]
= [tex]9(a^{5})^{2}[/tex]
= [tex]9a^{(5+5)}[/tex] [Since [tex]a^{b}\times a^{b}=a^{b+b}[/tex]]
= [tex]9a^{10}[/tex]
Therefore, area of the pool is [tex]9a^{10}[/tex].
