Two cyclists, 108 miles apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 4hr later, at what average speed is each cyclist traveling ?
9 and 18 divide 108 miles in 4 hours which is 27 and next since of. One of them is twice faster. Divde 27 into 3. And you get 9 and the faster obe. Is 18 mph.
