Explanation:
As it is given that the element contains a total of 8 electrons. So, electronic distribution of this element will be 2, 6.
That is, there will be two electrons present in first shell and there will be six electrons present in second valence shell.
Here, we also get to know that this element contains 6 valence electrons hence, it is a group 16 element.
Thus, we can conclude that if an element contains 8 electrons then 6 electrons will be placed in the 2nd valence shell.
The number of electrons that will be placed in the second valence shell is 6 electrons
From a background understanding of the arrangement of electrons around the nucleus of atom, we understood that the 1st shell will hold a maximum of 2 electrons, while other shells a maximum of 8 electrons.
Considering the question given above, we have:
Total electron = 8 electrons
Remaining electrons = 8 – 2
Since the remaining elections is not more than 8 electrons, they will be place in the 2nd shell i.e
Thus, we can conclude that the 2nd shell will have 6 electrons.
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