Answer: 92mg of ethyl alcohol
2 milli molar of ethyl alcohol means 2 milli mole glucose for 1 liter of water. Since we want to make 1L of solution, then the amount of ethyl alcohol needed is: 2 milli mole/l x 1l= = 2 x 10^-3 mole
Ethyl alcohol molecular weight is 46g/mole, then 2 mili mole of glucose is= 2x 10^-3 mole x 46 grams/mole= 92 grams x 10^-3= 92mg
