Question

help please!!! can you show me how to do this??

Answer 1

$\frac{3x - 2}{x^{2} - 2x - 3} - \frac{1}{x - 3} = \frac{3x -2}{(x + 1)(x - 3)} - \frac{1}{x - 3} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{1(x + 1)}{(x + 1)(x - 3)} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{x + 1}{(x + 1)(x - 3)} = \frac{2x - 3}{(x + 1)(x - 3)}$