Question

The flame temperature in an automobile engine is 1699 °f, and the exhaust is emitted at 229 °f. what is the carnot efficiency of the engine?

Answer 1

Solution:

η =  Efficiency ; T(hot) =Temperature of the Hot source ; T(cold) = Temperature of the Cold Sink ;

η = 1 – {T(cold)/T(hot)}

η = 1 – {229 / 1699}

η = 0.6809748595199822 x 100

η = 68.09 %

The answer is 68.09 %,  you can use the Carnot Thermal efficiency Calculator in the Internet.

Answer 2

The correct statement is that the Carnot efficiency of the automobile engine is calculated as 68% when the temperature of the flame is 1699 degrees and exhaust temperature is capped at 229 degrees.

The calculation of the Carnot efficiency of the automobile engine can be done by applying the values  in the given information to the formula of the Carnot efficiency.

Calculation of Carnot efficiency

• The formula for the calculation of Carnot efficiency of a heat engine is as below,

• $\rm Carnot\ Efficiency\ = 1- \dfrac{Temperature\ of\ Hot\ Reservoir\ - Temperature\ of\ Cold\ Temperature}{Temperature\ of\ Hot\ Reservoir}$

• Now applying the given values to the formula above, we get,

• $\rm Carnot\ Efficiency= 1- \dfrac{1699\ - 229}{1699} x\ 100\\\\\rm Carnot\ Efficiency= 0.68$

Hence, the correct statement is that the Carnot efficiency of an automobile engine is calculated as 68% when the flame temperature is 1699 degree Fahrenheit and exhaust temperature is 299 degrees.

Learn more about Carnot Efficiency here:

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