Question

If a commuter train averages 62 miles per hour between stops that are 18 miles apart, about how many minutes does it take the train to travel the distance between the two stops?

Answer 1

first find what percent 18 miles is of 62 miles (62 divided by 18) which is 3.4444 If 18 miles is 3.444 x smaller than 62 miles per hour and we know one hour is 60 minutes the time it takes to get the 18 miles between stops would be 60 minutes divided by 3.4444. The answer is 17.41957961 minutes (round how you see fit)

Answer 2

Answer:  The required number of minutes is 17.42 minutes.

Step-by-step explanation:  Given that a computer train averages 62 miles per hour between stops that are 18 miles apart.

We are to find the number of minutes that the train will take to travel the distance between the two stops.

We know that

the distance, time and speed is related by the following formula :

$S=\dfrac{D}{T}.$

According to the given information, we have

S = 62 miles per hour  and  D = 18 miles.

Therefore, we get

$S=\dfrac{D}{T}\\\\\\\Rightarrow 62=\dfrac{18}{T}\\\\\\\Rightarrow T=\dfrac{18}{62}~\textup{hour}\\\\\\\Rightarrow T=\dfrac{9}{31}\times60~\textup{minutes}=17.42~\textup{minutes}.$

Thus, the required number of minutes is 17.42 minutes.