Answer:
49 mg
Step-by-step explanation:
You want the mass of an isotope in 2002 if it was 110 mg in 1990 and decayed to 90 mg in 1993.
The exponential function modeling the remaining amount (y) after t years can be written as ...
y = (initial amount) × (decay factor)^(t/(decay period))
where the decay factor is the multiplier of the initial amount after a time equal to the decay period.
Here, we have ...
initial amount = 110 mg
decay factor = 90/1110
decay period = 3 years . . . . from 1990 to 1993
This means we can write the function describing the remaining amount as ...
[tex]y=110\left(\dfrac{90}{110}\right)^{\dfrac{t}{3}}[/tex]
After the 12 years from 1990 to 2002, the amount remaining is ...
[tex]y=(110\text{ mg})\left(\dfrac{90}{110}\right)^{\dfrac{12}{3}}\approx49\text{ mg}[/tex]
The mass of the remaining isotope in the year 2002 is about 49 mg.