Question

The line has a slope of −3 and passes through point (4, 8). Find the missing coordinates of the points on a line (5, ...), (6, ...), (3, ...), (10, ...)

Answer 1

Answer:

(5, 5 )

Step-by-step explanation:

A line with a slope m = - 3, means

$\frac{vertical}{horizontal}$ = $\frac{-3}{1}$

That is subtract 3 from the y- coordinate and add 1 to the x- coordinate

(4, 8 ) → (4 + 1, 8 - 3 ) → (5, 5 )

The other point on the line would be (5, 5 )

As a check using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

let (x₁, y₁ ) = (4, 8 ) and (x₂, y₂ ) = (5, 5 ) , then

m = $\frac{5-8}{5-4}$ = $\frac{-3}{1}$ = - 3

Thus (5, 5 ) is a point on the line with slope of - 3