KngSngh3710 KngSngh3710
  • 27-08-2017
  • Mathematics
contestada

If y=x^2+kx-k, for what values of k will the quadratic have two real solutions

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meerkat18
meerkat18 meerkat18
  • 08-09-2017
We use the Factor and Remainder Theorem to answer this problem. Suppose you have a polynomial in terms of x. When you substitute a value x and the answer would be zero, then that means that x is a factor of the polynomial producing 2 real solutions. If the answer is nonzero, then it is not a factor. Therefore, we also have to know at what value of x should we use. Let's assume x-2. Applying the factor and remainder theorem:

y = x²+kx-k = 0
(2)
² + k(2) - k = 0
k = -4


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