The inner and outer surfaces of a 5m x 6m brick wall of thickness 30 cm and thermal conductivity 0.69 w/m.0 c are maintained at temperature of 20 0 c and 50 c, respectively. determine the rate of heat transfer through the wall, in w.
The working equation to be used here is written below:
Q = kA(T₁ - T₂)/Δx where Q is the rate of heat transfer k is the heat transfer coefficient A is the cross-sectional area of the wall T₁ - T₂ is the temperature difference between the sides of the wall Δx is the thickness of the wall
The solution is as follows:
Q = (0.69 W/m²·°C)(5 m × 6 m)(50°C - 20°C)/(30 cm * 1 m/100 cm) Q = 2,070 W/m
