Respuesta :
Answer:
In 2007
Step-by-step explanation:
To find out when the population of Kenya will reach 50,000,000 people with an annual rate of increase of 4.1%, we can use the exponential growth formula:
[tex] P(t) = P_0 \times (1 + r)^t [/tex]
Where:
- [tex] P(t) [/tex] is the population at time [tex] t [/tex].
- [tex] P_0 [/tex] is the initial population (in 1990 in this case).
- [tex] r [/tex] is the annual rate of increase (in decimal form).
- [tex] t [/tex] is the time in years.
In this case, [tex] P_0 = 25,000,000 [/tex], [tex] r = 0.041 [/tex] (4.1% expressed as a decimal), and we want to find [tex] t [/tex] when [tex] P(t) = 50,000,000 [/tex].
So, we set up the equation:
[tex] 50,000,000 = 25,000,000 \times (1 + 0.041)^t [/tex]
Now, we need to solve for [tex] t [/tex].
Start by dividing both sides by [tex] 25,000,000 [/tex]:
[tex] 2 = (1 + 0.041)^t [/tex]
Now, take the natural logarithm (ln) of both sides:
[tex] \ln(2) = \ln\left((1 + 0.041)^t\right) [/tex]
Using the property of logarithms that [tex] \ln(a^b) = b \cdot \ln(a) [/tex], we have:
[tex] \ln(2) = t \cdot \ln(1 + 0.041) [/tex]
Now, solve for [tex] t [/tex]:
[tex] t = \dfrac{\ln(2)}{\ln(1 + 0.041)} [/tex]
[tex] t = \dfrac{\ln(2)}{\ln(1.041)} [/tex]
Using a calculator:
[tex] t \approx \dfrac{0.6931471806}{0.04018178963} [/tex]
[tex] t\approx 17.25028146 [/tex]
[tex] t \approx 17.25 \textsf{(in 2 d.p.)} [/tex]
So, it will take approximately 17.25 years from 1990 for the population of Kenya to reach 50,000,000 people with an annual rate of increase of 4.1%.
Since we can't have a fraction of a year in this context, we round up to the nearest whole number.
Therefore, the population is projected to reach 50,000,000 people around the year [tex]1990 + 17 = 2007[/tex].

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