Question

Find the area of the composite figure.
First, find the area of the triangle.
Triangle
Area = [?] cm²
Parallelogram
Area = [] cm²
Total Area of
bh
12
4 cm
10 cm
6 cm
10 cm
Composite Figure = [ ] cm²

Answer 1

Answer:

The area of the figure is 80 cm sq.

Step-by-step explanation:

The area of the traingle

= 1/2×10×4 = 20 cm sq.

The area of the parallelogram

= 1/2× (10+10)×6

= 60 cm sq

The area of the figure

= 80 cm sq.

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Answer 2

Answer:

$A_{\textsf{triangle}} = 20 \, \textsf{cm}^2$

$A_{\textsf{rectangle}} = 60 \, \textsf{cm}^2$

$\textsf{Total Area} = 80 \, \textsf{cm}^2$

Step-by-step explanation:

To find the area of the composite figure, we first need to find the area of each individual component and then sum them up.

Area of the Triangle:

Given:

• Base of the triangle $= 10 \, \textsf{cm}$
• Height of the triangle $= 4 \, \textsf{cm}$

The area $A$ of a triangle is given by the formula:

$A_{\textsf{triangle}} = \dfrac{1}{2} \times \textsf{Base} \times \textsf{Height}$

$A_{\textsf{triangle}} = \dfrac{1}{2} \times 10 \times 4$

$A_{\textsf{triangle}} = 20 \, \textsf{cm}^2$

Area of the Rectangle:

Given:

• Length of the rectangle $= 10 \, \textsf{cm}$
• Width of the rectangle $= 6 \, \textsf{cm}$

The area $A$ of a rectangle is given by the formula:

$A_{\textsf{rectangle}} = \textsf{Length} \times \textsf{Width}$

$A_{\textsf{rectangle}} = 10 \times 6$

$A_{\textsf{rectangle}} = 60 \, \textsf{cm}^2$

Now, to find the total area of the composite figure, we add the areas of the triangle and the rectangle:

$\textsf{Total Area} = A_{\textsf{triangle}} + A_{\textsf{rectangle}}$

$\textsf{Total Area} = 20 + 60$

$\textsf{Total Area} = 80 \, \textsf{cm}^2$

So, the total area of the composite figure is $80 \, \textsf{in}^2$.