Question

A linear function contains the following points.
X
y
-2,8
0,6
What are the slope and y-intercept of this function?
A. The slope is 1.
The y-intercept is (0, 6).
B. The slope is -1.
The y-intercept is (6, 0).
C. The slope is 1.
The y-intercept is (6, 0).
D. The slope is -1.
The y-intercept is (0, 6).

Answer 1

Using the point (x,y) in this case (-2,8) (0,6)

Use slope formula [(y2-y1)/(x2-x1)]

6-(8)
Slope = ——— = -2/2 = -1
0-(-2)

Slope(m)= -1

Now using either point substitute m and the point (x,y) into slope intercept form

Y=mX+b

6= (-1)(0) + b

6= (0) + b

B = 6

Answer D

Slope = -1

Y intercept (0,6)

Answer 2

Answer:

D. The slope is -1.

The y-intercept is (0, 6).

Step-by-step explanation:

To find the slope ($m$) and y-intercept ($b$) of a linear function from the given points $(-2, 8)$ and $(0, 6)$, we can use the slope-intercept form of a linear equation:

$\Large\boxed{\boxed{y = mx + b}}$,

where

• $m$ is the slope and
• $b$ is the y-intercept.

Given the points $(-2, 8)$ and $(0, 6)$, we can use the formula for slope:

$m = \dfrac{{y_2 - y_1}}{{x_2 - x_1}}$

where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of the two points.

Using the points $(-2, 8)$ and $(0, 6)$, we have:

$m = \dfrac{{6 - 8}}{{0 - (-2)}} = \dfrac{{6 - 8}}{{2}} = \dfrac{{-2}}{{2}} = -1$

Now that we have the slope ($m = -1$), we can use one of the given points to find the y-intercept ($b$).

Let's use the point $(0, 6)$ and substitute the values into the equation $y = mx + b$:

$6 = (-1)(0) + b$

$6 = b$

Therefore, the y-intercept ($b$) is 6.

So, the answer is:

D. The slope is -1.

The y-intercept is (0, 6).