Question

If 1.38×1022 atoms of element y have a mass of 1.50 g, what is the identity of y? express your answer as a chemical symbol.

Answer 1

1,38×10²² = 0,138×10²³

0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol

It's ZINC (Zn)

:•)

Answer 2

"Zinc (Zn)" has the atomic mass "65.4". A further solution is provided below.

Given:

• Number of atoms = $1.388\times 10^{22}$
• Mass of element = 1.50 g

By using the formula,

→ $Mole = \frac{Mass}{\frac{Molar}{Atomic \ mass} } = \frac{\frac{Number \ of \ molecules}{Atoms} }{Avogadro \ number}$

then,

→ $\frac{Mass}{Atomic \ mass} =\frac{Number \ of \ atoms}{Avogadro \ number}$

By substituting the given values, we get

→             $\frac{1.50 }{x} = \frac{1.38\times 10^{22}}{6.022\times 10^{23}}$

→                $x = \frac{1.50\times 6.022\times 10^{23}}{1.38\times 10^{22}}$

→                   $=65.456$ (Zinc)  

Thus the above is the right answer.

Learn more about zinc here:

https://brainly.com/question/10872991