Question

What is the point-slope form of a line with slope 4/5 that contains the point
(-2, 1)?
A. y+1 = (x+2)
B. y-1 = (x+2)
C. y + 1 = (x-2)
D. y-1 = (x-2)

Answer 1

Answer:

B.

Step-by-step explanation:

y - 1 = 4/5(x + 2)

Answer 2

Answer:

$\textsf{B.}\quad y-1=\dfrac{4}{5}(x+2)$

Step-by-step explanation:

To find the point-slope form of a line with slope 4/5 that contains the point (-2, 1), we can use the point-slope formula:

$\boxed{\begin{array}{l}\underline{\textsf{Point-slope form of a linear equation}}\\\\y-y_1=m(x-x_1)\\\\\textsf{where:}\\ \phantom{ww}\bullet\;\textsf{ m is the slope.}\\\phantom{ww}\bullet\;\textsf{ (x_1,y_1) is a point on the line.}\end{array}}$

In this case:

$m=\dfrac{4}{5}$

$x_1=-2$

$y_1=1$

Substitute these values into the point-slope formula:

$y-1=\dfrac{4}{5}(x-(-2))$

Simplify:

$y-1=\dfrac{4}{5}(x+2)$

Therefore, the point-slope form of the line is:

$\Large\boxed{\boxed{y-1=\dfrac{4}{5}(x+2)}}$