Answer:10%
Step-by-step explanation:To determine the chance of rejecting the whole book, we need to find the probability of encountering at least one error page in a random selection of 10 pages.
Since there are 2 error pages out of 200 total pages, the probability of selecting an error page on any given page is 2200=11002002=1001.
The probability of not selecting an error page on any given page is therefore 1−1100=991001−1001=10099.
To find the probability of not encountering any error pages in a selection of 10 pages, we need to multiply the probability of not selecting an error page on any given page by itself 10 times (since each selection is independent):
(99100)10(10099)10
Calculating this:
(99100)10≈0.904382075(10099)10≈0.904382075
This is the probability of not encountering any error pages in a selection of 10 pages. However, we're interested in the probability of encountering at least one error page, which is the complement of this probability.
So, the probability of encountering at least one error page in a selection of 10 pages is:
1−0.904382075≈0.0956179251−0.904382075≈0.095617925
This is approximately 9.56%. Since this probability is less than 10%, the chance of rejecting the whole book would be 10%. Therefore, the correct answer is:
d) 10%
