Question

If the atomic radius of aluminum is 0.143 nm, calculate the volume of its unit cell in cubic meters.

Answer 1

The unit cell of Aluminum is a face-centered cubic structure. This lattice unit cell consists of 4 atoms per unit cell. The volume of the unit cell is a³ where a is the length of the side of the unit cell. In terms of radius r, volume is equal to:

V = (4r/√2)³
V = (4(0.143×10⁻⁹ m)/√2)³
V = 6.62×10⁻²⁹ m³

Answer 2

We have that the volume of the unit cell in cubic meters.  is mathematically given as

V = 6.62×10^(-29) m³

Volume of unit cell

Question Parameters:

The atomic radius of aluminum is 0.143 nm,

The volume of the unit cell is l^3 and l  signifies the length of the side of the unit cell.

Generally the equation for the Volume is mathematically given as

V = (4r/√2)³

Therefore

V = (4(0.143×10⁻⁹ m)/√2)³

V = 6.62×10^(-29) m³

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