Answer:
Explanation:
To find the resistance of a bulb rated at 330 volts and 110 watts, we can use the formula relating power, voltage, and resistance:
1. Given that power (P) = 110 watts and voltage (V) = 330 volts, we can use the formula P = V^2 / R, where R is the resistance.
2. Rearranging the formula to solve for resistance, we get R = V^2 / P.
3. Substituting the values, R = 330^2 / 110 = 9900 / 110 = 90 ohms.
Therefore, the resistance of one bulb is 90 ohms. When three such bulbs are connected, the total resistance in the circuit would depend on how they are connected (in series or parallel) and would need further information to calculate accurately.
