Question

consider the graph of Bx + Cy = A where A, B, and C are all positive constants. (a) Find the coordinates of the x-intercept and Y intercept. Use upper case letters.

Answer 1

To find the x-intercept, plug in 0 for y and isolate x.

Bx + C(0) = A
Bx = A
X = A/B
And the x-intercept would be (A/B, 0).

The same principle applies to finding the y-intercept.

B(0) + Cy = A
Cy = A
y = A/C
And the y-intercept would be (0, A/C).

Hope this helps!

Answer 2

The intercepts of a function are the points where the function crosses the x or y-axis.

• The coordinates of the x-intercept is; $( \frac AB,0)$.
• The coordinates of the y-intercept is; $(0, \frac AC)$

The function is given as:

$Bx + Cy = A$

Substitute 0 for y, to calculate the x-intercept

$Bx + Cy = A$

$Bx + C \times 0 = A$

$Bx = A$

Make x the subject

$c = \frac AB$

So, the coordinates of the x-intercept is; $( \frac AB,0)$

Substitute 0 for x, to calculate the y-intercept

$Bx + Cy = A$

$B\times 0 + Cy = A$

$Cy = A$

Make y the subject

$c = \frac AC$

So, the coordinates of the y-intercept is; $(0, \frac AC)$

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