Question

Write the chemical symbols for three different atoms or atomic anions with 36 electrons

Answer 1

Explanation:

An element with atomic number 36 is krypton and symbol which represents it is Kr.

Atomic number of bromine is 35 and when it gains an electron it forms bromine ion ($Br^{-}$). Total number of electrons in $Br^{-}$ are 36.

Atomic number of Selenium is 34. When it gains two electrons then it forms $Se^{2-}$ ion. Therefore, total number of electrons present in $Se^{2-}$ ion are 36.

Hence, chemical symbols for three different atoms or atomic anions with 36 electrons are Kr, $Br^{-}$, and $Se^{2-}$.

Answer 2

Kr, Br⁻ y Se²⁻ are isoelectronic, that is, they have the same number of electrons (36).

Krypton has an atomic number of 36, which means it has 36 protons. Since it is electrically neutral, it has the same number of protons (positive charges) as electrons (negative charges). Thus, Kr has 36 electrons.

Bromine has an atomic number of 35, which means it has 35 protons and 35 electrons. When it gains 1 electron, it forms the anion Br⁻, which has 35 + 1 = 36 electrons.

Selenium has an atomic number of 34, which means it has 34 protons and 34 electrons. When it gains 2 electrons, it forms the anion Se²⁻, which has 34 + 2 = 36 electrons.

Kr, Br⁻ y Se²⁻ are isoelectronic, that is, they have the same number of electrons (36).

You can learn more about isoelectronic series here: https://brainly.com/question/19157981