To solve for \( x \) in the sequence \( 29, x, 41, 40 \), we can observe that the sequence is likely arithmetic because the difference between consecutive terms seems to be constant.
To find \( x \), we can use the fact that in an arithmetic sequence, the common difference between consecutive terms remains the same.
Given the sequence: 29, x, 41, 40
The difference between consecutive terms:
\( x - 29 = 41 - x = 40 - 41 \)
Let's solve for \( x \) using any of these equations. Let's take \( x - 29 = 41 - x \):
\( x - 29 = 41 - x \)
Adding \( x \) to both sides and adding 29 to both sides:
\( 2x = 41 + 29 \)
\( 2x = 70 \)
Dividing both sides by 2:
\( x = 35 \)
So, \( x = 35 \).
