Question

Determine the component of this force along X and Y directions. A force of 500N is acting at a point making an angle of 60° with the horizontal. ​

Answer 1

Answer:

The component of the force along the x-direction is 250 N, and along the y-direction is 433 N.

Explanation:

Horizontal Component, Y = 500N × cos 60⁰

Vertical Component, X = 500N × sin 60°

Y = 500 × 0.5 = 250N

X = 500× √3/2 = 250 × √3 ≈ 433N