Respuesta :
Answer:
[tex]y = -\dfrac{5}{6}x - 8[/tex]
Step-by-step explanation:
To find the equation of a line passing through the points [tex](0, -8)[/tex] and [tex](-6, -3)[/tex], we can use the point-slope form of a linear equation, which is:
[tex] y - y_1 = m(x - x_1) [/tex]
where [tex](x_1, y_1)[/tex] are the coordinates of a point on the line, and [tex]m[/tex] is the slope of the line.
First, let's find the slope ([tex]m[/tex]) using the given points:
[tex] m = \dfrac{y_2 - y_1}{x_2 - x_1} [/tex]
[tex] m = \dfrac{-3 - (-8)}{-6 - 0} [/tex]
[tex] m = \dfrac{-3 + 8}{-6} [/tex]
[tex] m = \dfrac{5}{-6} [/tex]
[tex] m = -\dfrac{5}{6} [/tex]
Now that we have the slope, let's use one of the points (let's use [tex](0, -8)[/tex]) and the slope to write the equation of the line:
[tex] y - (-8) = -\dfrac{5}{6}(x - 0) [/tex]
[tex] y + 8 = -\dfrac{5}{6}x [/tex]
To write the equation in slope-intercept form ([tex]y = mx + b[/tex]), we need to solve for [tex]y[/tex]:
[tex] y = -\dfrac{5}{6}x - 8 [/tex]
So, the equation of the line passing through the points [tex](0, -8)[/tex] and [tex](-6, -3)[/tex] is:
[tex]y = -\dfrac{5}{6}x - 8[/tex]
Answer:
y = -5/6x - 8
Step-by-step explanation:
We use the point-slope form y - y1 = m(x - x1).
First, we find the slope with the two points (0,-8) and (-6,-3).
We see the y increase by 5 and the x decrease by 6, so the slope is
m = -5/6
Now, we subtitute the number in.
y - (-8) = -5/6(x - 0)
y + 8 = -5/6x
y = -5/6x - 8