Question

1. Divide Rs. 1870 in three parts such that half of the first part, one-third of the second part and one-sixth of the third part are equal.

Answer 1

Answer:the three parts are Rs. 340, Rs. 510, and Rs. 1020, r

Step-by-step explanation:

Let's denote the three parts as x, y, and z.According to the given conditions:Half of the first part: 1/2 * xOne-third of the second part: 1/3 * yOne-sixth of the third part: 1/6 * zAccording to the problem, these three quantities are equal. So, we can set up the equation:1/2 * x = 1/3 * y = 1/6 * zLet's denote this common value as "k". So, we have:1/2 * x = 1/3 * y = 1/6 * z = kNow, we can solve for x, y, and z:1/2 * x = k

x = 2k1/3 * y = k

y = 3k1/6 * z = k

z = 6kWe know that the sum of these three parts equals Rs. 1870:

Answer 2

Answer:the three parts are Rs. 340, Rs. 510, and Rs. 1020, r

Step-by-step explanation:

Let's denote the three parts as x, y, and z.According to the given conditions:Half of the first part: 1/2 * xOne-third of the second part: 1/3 * yOne-sixth of the third part: 1/6 * zAccording to the problem, these three quantities are equal. So, we can set up the equation:1/2 * x = 1/3 * y = 1/6 * zLet's denote this common value as "k". So, we have:1/2 * x = 1/3 * y = 1/6 * z = kNow, we can solve for x, y, and z:1/2 * x = k

x = 2k1/3 * y = k

y = 3k1/6 * z = k

z = 6kWe know that the sum of these three parts equals Rs. 1870:x + y + z = 1870Substituting the values of x, y, and z:2k + 3k + 6k = 1870

11k = 1870Solving for k:k = 1870 / 11

k ≈ 170Now, we can find the values of x, y, and z:x = 2k ≈ 2 * 170 = 340

y = 3k ≈ 3 * 170 = 510

z = 6k ≈ 6 * 170 = 1020So, the three parts are Rs. 340, Rs. 510, and Rs. 1020, respectively.