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Sodium carbonate reacts with dillute hydrochloric acid.
Na2CO3+2HCL=2NaCl+H2O+CO2
A sample containing 0.0800 mol of sodium carbonate is added to a solution containing 0.100 mol of hydrochloric acid.
Which volume of carbon dioxide is produced, measured at room temperature and pressure?

Respuesta :

Answer:

To determine the volume of carbon dioxide produced, we need to use the ideal gas law equation:

PV = nRT

Where:

P = pressure (at room temperature and pressure, it is approximately 1 atm)

V = volume of gas

n = number of moles of gas

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature in Kelvin (room temperature is approximately 298 K)

From the balanced chemical equation, we can see that 1 mole of sodium carbonate (Na2CO3) produces 1 mole of carbon dioxide (CO2).

Given:

Number of moles of sodium carbonate (Na2CO3) = 0.0800 mol

Number of moles of hydrochloric acid (HCl) = 0.100 mol

Since the stoichiometric ratio between sodium carbonate and carbon dioxide is 1:1, the number of moles of carbon dioxide produced is also 0.0800 mol.

Now, we can calculate the volume of carbon dioxide using the ideal gas law equation:

PV = nRT

V = (nRT) / P

V = (0.0800 mol * 0.0821 L·atm/(mol·K) * 298 K) / 1 atm

V ≈ 1.93 L

Therefore, approximately 1.93 liters of carbon dioxide are produced, measured at room temperature and pressure.

#Hope it helps :)

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