Respuesta :

Problem 60) The only natural number is the number 62 (assuming the number is 62 and not some decimal value;it's impossible to tell because it appears to be cut off). Recall that the set of natural numbers is the set {1, 2, 3, 4, ...} which is synonymous with the set of counting numbers.

------------------------------------------------

Problem 62) Irrational numbers are numbers that we CANNOT write as fractions of whole numbers. In this case, pi is irrational and so is sqrt(17)

It is impossible to write pi as a ratio of two integers (in the form p/q where q is nonzero). The same applies to sqrt(17).

------------------------------------------------

Problem 64)

There are two nonnegative integers and they are: 0 and 62 (keeping with the same assumption made back in problem 60 above). All you do here is list whole numbers that aren't negative.

Answer:

(60) In the given numbers only 62 is natural number.

(62) π and [tex]\sqrt{17}[/tex] are irrational number.

(64) Only 0 and 62 are non-negative integers.

Step-by-step explanation:

The given numbers are

[tex]-83,-4.7,0,\frac{5}{9},2.\overline{16},\pi,62[/tex]

Part (60)

Natural number: All positive non zero integers are known as natural numbers. For example:-1, 2, 3, ....

In the given numbers only 62 is natural number.

Part (62)

Irrational numbers: If a real number cannot be expressed as a ratio of two integers, then it is known as irrational number. For example:- √2, 0.222..,π.

In the given numbers only π and [tex]\sqrt{17}[/tex] are irrational number.

Part (64)

Non-negative integers: All positive integers including 0 are known as non-negative integers.

In the given numbers only 0 and 62 are non-negative integers.

ACCESS MORE