Conejosbear1
Conejosbear1
20-08-2017
Mathematics
contestada
Is the answer no solution?
Respuesta :
kphung76127
kphung76127
20-08-2017
Cross multiply and solve
1(y^2-9)=6(y-3)
y^2-9= 6y-18
y^2-6y-9+18=0
y^2-6y+9=0
(y-3)(y-3)=0
(y-3)=0
y=3
When you plug y in however, it makes the denominator 0, making both fractions undefined.
Final answer: No real solution
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