Question

The probability that an individual is left-handed is 0.12. in a class of 39 students, what is the probability of finding five left-handers

Answer 1

Answer:

0.1856

Step-by-step explanation:

Given that prob that an individual is left-handed is 0.12.

n = sample size = no of students = 39

q = 1-p = 0.88

Let X be the no of students who are left handed.

X is binomial since each student is independent of the other and there are only two outcomes

X:Bin(39, 0.12)

Probability of finding five left-handers

=P(X=5)

= 39C5 (0.12)^5 (0.88)^34

=0.1856

Answer is 0.1856

Answer 2

The probability of finding five left-handers in a class of 39 students is 0.186

The given parameters are:

n = 39 -- the total number of students

p = 0.12 -- the probability of finding a left hander

r = 5 -- the number of left-hander to find

The probability of finding five left-handers is calculated using the following binomial probability

$P(x = r) = ^nC_r *p^r * (1 - p)^{n -r}$

So, we have:

$P(x = 5) = ^{39}C_5 *0.12^5 * (1 - 0.12)^{39 -5}$

$P(x = 5) =575757 *0.12^5 * (1 - 0.12)^{34$

$P(x = 5) =0.186$

Hence, the probability of finding five left-handers in a class of 39 students is 0.186

Read more about probabilities at:

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