the equation of a line that passes through the points [tex](x_1,y_1)[/tex] and has a slope of m is
[tex]y-y_1=m(x-x_1)[/tex]
so
we want the eqaution of a line that passes through the point (8,-8) and has a slope of 3
x₁=8
y₁=-8
m=3
so
[tex]y-y_1=m(x-x1)[/tex]
[tex]y-(-8)=3(x-(8))[/tex]
[tex]y+8=3(x-8)[/tex]
answer is D