For the left-hand triangle we know: [tex](x+7)\°+(3x-18)\°+(x-9)\°=180\°[/tex].
Solving for [tex]x[/tex] we have:
[tex]5x\°-20\°=180\°[/tex]
[tex]5x\°=200\°[/tex]
[tex]x=40\°[/tex]
So the angles on the left are: 47,31 and 102 degrees.
On the right we have [tex]y\°+(x+21)\°+(x+17)\°=180\°[/tex]
Substituting known values and solving we get:
[tex]y\°+61\°+47\°=180\°[/tex]
[tex]y=72\°[/tex}
So the angles on the right are, 72, 61 and 47 degrees.
