Question

f(x)=2x-8 g(x)=x^(2) Find a value of x such that fg(x)=0.

Answer 1

Answer:

x = ± 2

Step-by-step explanation:

to find f(g(x)), substitute x = g(x) into f(x)

f(g(x))

= f(x²)

= 2x² - 8

Now equate f(g(x)) to zero, that is

2x² - 8 = 0 ( add 8 to both sides )

2x² = 8 ( divide both sides by 2 )

x² = 4 ( take square root of both sides )

$\sqrt{x^2}$ = ± $\sqrt{4}$ , that is

x = ± 2