Answer: 68.345m and 3.735s
Explanation:
Using what we know, we can solve for time using the equation vf=vi+at
(0m/s)=(36.6m/s)+(-9.8m/s²)t
t=3.735s
vf in this case is equal to zero because max height is where the ball changes directions (initially moves up, reaches max height, falls back down) and acceleration equals -9.8m/s² because it is Earth's gravitational acceleration
We can solve for Δy by using the equation vf²=vi²+2aΔy OR Δy=(1/2)at²+(vi)t
using the first equation: (0m/s)²=(36.6m/s)²+2(-9.8m/s²)Δy
Δy=68.345m
using the second equation: Δy=(1/2)(-9.8m/s²)(3.735s)²+(36.6m/s)(3.735s)
Δy=68.345m
