Respuesta :
To draw the pre-mRNA and mature mRNA, we need to remove the introns (lowercase letters) and keep the exons (uppercase letters). Then, we'll translate the mRNA sequence into protein using the genetic code.
Given the DNA segment:
```
5'-AGGAAATGAAATGCCAgaattgccggatgacGGTCAGCaatcgaGCACATTTGTGATTTACCGT-3'
```
Transcribing the DNA sequence into pre-mRNA:
```
5'-AGGAAAUGAAAUGCCAugccggatgacGGUCAGCaatcgaGCACAUUUGUGAUUUACCGU-3'
```
Removing the introns, we get the mature mRNA:
```
5'-AGGAAAUGAAAUGCCAUGGUCAGCAUGCAGCACAUUUGUGAUUUACCGU-3'
```
Now, we will translate the mRNA into protein using the genetic code:
| Codon | Amino Acid |
|---------|-------------|
| AUG | Methionine (Start) |
| AAA | Lysine |
| AUG | Methionine (Start) |
| CCA | Proline |
| UGG | Tryptophan |
| CAG | Glutamine |
| CAU | Histidine |
| UUU | Phenylalanine |
| GUA | Valine |
| UUU | Phenylalanine |
| ACC | Threonine |
| GUU | Valine |
The protein sequence would be:
```
Methionine - Lysine - Methionine - Proline - Tryptophan - Glutamine - Histidine - Phenylalanine - Valine - Phenylalanine - Threonine - Valine
```
Identifying the 5'UTR (5' untranslated region) and 3'UTR (3' untranslated region):
- The 5'UTR is the sequence before the start codon (AUG), which is untranslated but plays a role in initiation of translation. In this case, it is "AGGAAAU".
- The 3'UTR is the sequence after the stop codon (UGA), which is also untranslated and often plays a role in regulation of mRNA stability and translation. In this case, it is "ACCGU".