Question

HELPP ANYONE????

The zero of the function in A(C)=9x^2-25/3x+5 is....

-5/3
5/3
5

Answer 1

A(C)=9x^2-25/3x+5 = [3x+5)(3x-5)] / (3x -5) = 3x + 5

The zero of the function, 
3x + 5 = 0
3x = -5
x = -5/3

answer
-5/3