To balance the equation Al2(SO4)3 + 3 BaCl2 → 3BaSO4 + 2 AlCl3, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
Here's the balanced equation:
Al2(SO4)3 + 3 BaCl2 → 3 BaSO4 + 2 AlCl3
Now, let's calculate the number of moles of each product produced when 300g of BaCl2 is used.
To find the number of moles of BaCl2, we need to use its molar mass. The molar mass of BaCl2 is:
BaCl2: Ba (137.33 g/mol) + 2 Cl (35.45 g/mol) = 208.23 g/mol
To calculate the number of moles, we divide the mass by the molar mass:
Moles of BaCl2 = 300 g / 208.23 g/mol = 1.44 mol
According to the balanced equation, the ratio of moles of BaCl2 to moles of BaSO4 is 3:3, and the ratio of moles of BaCl2 to moles of AlCl3 is 3:2.
So, using the 1.44 moles of BaCl2, we can calculate the number of moles of BaSO4 and AlCl3:
Moles of BaSO4 = 1.44 mol × (3 mol BaSO4 / 3 mol BaCl2) = 1.44 mol
Moles of AlCl3 = 1.44 mol × (2 mol AlCl3 / 3 mol BaCl2) = 0.96 mol
Therefore, when 300g of BaCl2 is used, 1.44 moles of BaSO4 and 0.96 moles of AlCl3 will be produced.
