Question

A 2.2-µF capacitor is first charged so that the electric potential difference is 6.0 V. How much additional charge is needed to increase the electric potential difference to 15.0 V?

Answer 1

Answer:

19.8-µC

Explanation:

To Calculate the additional charge needed, you can use the formula for the capacitance of a capacitor:

• Q = CV

where,

• Q is the charge
• C is the capacitance, (2.2-µF )
• V is the voltage.

We are given,

A 2.2-µF capacitor is first charged so that the electric potential difference is 6.0 V.

• Here the initial potential difference is 6.0 V

We need to calculate the additional charge needed to increase the electric potential difference to 15.0 V.

• So, the final potential difference will be 15.0 V
• Final potential- initial potential
• 15 - 6
• 9 V

Plug the required values in the above formula,

• Q = 2.2 × 9
• Q = 19.8-µC

Hence, The charge of 19.8-µC is needed to increase the electric potential difference to 15.0 V.