Question

5A of current flowing through a resistor for 2 minute produced 3000 j of heat. The value of the resistance is ________Solution in Tamil
A. 1Ω
B. 2Ω
C. 4Ω
D. 5Ω

Answer 1

Answer:

the value of the resistance is 1 Ω

Explanation:

The formula for calculating energy dissipated as heat in a resistor is:

• E = I²RT

Where,

• I is current
• R is Resistance
• T is time

we are given :

5A of current flowing through a resistor for 2 minute produced 3000 j of heat.

• Here, Current (I) = 5A
• Time (t) = 2 minutes = 120 seconds

Plug in the given values in the above formula

• 3000 = 5²*R*120
• 3000 = 25*R*120
• 3000 = 3000R

divide both sides by 3000

• R = 1 Ω

Hence, the value of the resistance is 1 Ω