Answer:
[tex]\textsf{C)}\quad y = -x^2+2[/tex]
Step-by-step explanation:
The provided graph shows a downward-opening parabola with the vertex at (0, 2).
A downward-opening parabola is characterized by a negative coefficient for the squared term. Among the provided options, the equations with a negative coefficient for x² are:
[tex]y= -2x^2-1[/tex]
[tex]y = -x^2+2[/tex]
As the graphed parabola crosses the y-axis at (0, 2), the correct equation that represents the graph is y = -x² + 2. When x = 0 is substituted into this equation, y = 2, corresponding to the y-intercept (0, 2).
So, the equation that is represented by the provided graph is:
[tex]\Large\boxed{\boxed{y = -x^2+2}}[/tex]