Answer: 3.210 x 10^24 formula units of Pb(C2H3O2)2 would weigh approximately 9.687 x 10^26 grams.
Explanation:
To calculate the weight of 3.210 x 10^24 formula units of Pb(C2H3O2)2 in grams, we need to use the molar mass of Pb(C2H3O2)2.
First, let's find the molar mass of Pb(C2H3O2)2:
- The atomic mass of lead (Pb) is 207.2 g/mol.
- The atomic mass of carbon (C) is 12.01 g/mol.
- The atomic mass of hydrogen (H) is 1.008 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
Now, we can calculate the molar mass of Pb(C2H3O2)2:
(2 x atomic mass of C) + (6 x atomic mass of H) + (4 x atomic mass of O) + atomic mass of Pb
= (2 x 12.01) + (6 x 1.008) + (4 x 16.00) + 207.2
= 24.02 + 6.048 + 64.00 + 207.2
= 301.268 g/mol
Next, we can use this molar mass to calculate the weight of 3.210 x 10^24 formula units of Pb(C2H3O2)2:
Weight = (number of formula units) x (molar mass)
= 3.210 x 10^24 x 301.268
= 9.687 x 10^26 grams
Therefore, 3.210 x 10^24 formula units of Pb(C2H3O2)2 would weigh approximately 9.687 x 10^26 grams.
