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To model Farmer Pisquet's gespils (y) as hours (x) increase, we can use the slope-intercept form of a linear equation, which is y = mx + b.
Let's break down the information given:
- Farmer Pisquet started with 94 gespils on his farm.
- Every hour, he exploded 3 more gespils.
Based on this information, we can determine the equation for Farmer Pisquet's gespils:
y = -3x + 94
In this equation:
- The coefficient of x, -3, represents the rate at which Farmer Pisquet's gespils decrease (3 gespils per hour).
- The constant term, 94, represents the initial number of gespils Farmer Pisquet started with.
Now, let's model Farmer Elentire's gespils (y) as hours (x) increase:
- Farmer Elentire started with 67 gespils on her farm.
- Every hour, she bought 6 more gespils.
Based on this information, we can determine the equation for Farmer Elentire's gespils:
y = 6x + 67
In this equation:
- The coefficient of x, 6, represents the rate at which Farmer Elentire's gespils increase (6 gespils per hour).
- The constant term, 67, represents the initial number of gespils Farmer Elentire started with.
These equations in slope-intercept form allow us to track the changes in the number of gespils for each farmer as hours increase.
I hope this clarifies the process of creating the equations. If you have any more questions, feel free to ask!
Answer:
Equation for Farmer Pisquet: [tex] y = -3x + 94 [/tex]
Equation for Farmer Elentire:[tex] y = 6x + 67 [/tex]
Step-by-step explanation:
To model Farmer Pisquet's gespils (y) as hours (x) increase, we can use the equation of a line in slope-intercept form:
[tex] \Large\boxed{\boxed{y = mx + b}} [/tex]
where:
- [tex] m [/tex] is the slope of the line, and
- [tex] b [/tex] is the y-intercept, the value of y when x = 0.
For Farmer Pisquet:
- The initial number of gespils is 94, so the y-intercept [tex] b [/tex] is 94.
- Every hour, he explodes 3 gespils, so the slope [tex] m [/tex] is -3 (because the number of gespils decreases by 3 each hour).
Therefore, the equation representing Farmer Pisquet's gespils is:
[tex] \Large\boxed{\boxed{y = -3x + 94 }}[/tex]
For Farmer Elentire:
- The initial number of gespils is 67, so the y-intercept [tex] b [/tex] is 67.
- Every hour, she buys 6 gespils, so the slope [tex] m [/tex] is 6 (because the number of gespils increases by 6 each hour).
Therefore, the equation representing Farmer Elentire's gespils is:
[tex]\Large\boxed{\boxed{ y = 6x + 67}} [/tex]
These equations model the number of gespils for each farmer as hours increase.