Farmer Pisquet started with 94 gespils on his farm. Every hour, he
exploded 3 more of them. Farmer Elentire started with 67 gespils on
her farm. Every hour, she bought 6 more of them.
Write a system of equations, in slope-intercept form, to model each
farmer's gespils (y) as hours (x) increase.

Respuesta :

Answer: Please Mark as Brainliest!

To model Farmer Pisquet's gespils (y) as hours (x) increase, we can use the slope-intercept form of a linear equation, which is y = mx + b.

Let's break down the information given:

- Farmer Pisquet started with 94 gespils on his farm.

- Every hour, he exploded 3 more gespils.

Based on this information, we can determine the equation for Farmer Pisquet's gespils:

y = -3x + 94

In this equation:

- The coefficient of x, -3, represents the rate at which Farmer Pisquet's gespils decrease (3 gespils per hour).

- The constant term, 94, represents the initial number of gespils Farmer Pisquet started with.

Now, let's model Farmer Elentire's gespils (y) as hours (x) increase:

- Farmer Elentire started with 67 gespils on her farm.

- Every hour, she bought 6 more gespils.

Based on this information, we can determine the equation for Farmer Elentire's gespils:

y = 6x + 67

In this equation:

- The coefficient of x, 6, represents the rate at which Farmer Elentire's gespils increase (6 gespils per hour).

- The constant term, 67, represents the initial number of gespils Farmer Elentire started with.

These equations in slope-intercept form allow us to track the changes in the number of gespils for each farmer as hours increase.

I hope this clarifies the process of creating the equations. If you have any more questions, feel free to ask!

msm555

Answer:

Equation for Farmer Pisquet: [tex] y = -3x + 94 [/tex]

Equation for Farmer Elentire:[tex] y = 6x + 67 [/tex]

Step-by-step explanation:

To model Farmer Pisquet's gespils (y) as hours (x) increase, we can use the equation of a line in slope-intercept form:

[tex] \Large\boxed{\boxed{y = mx + b}} [/tex]

where:

  • [tex] m [/tex] is the slope of the line, and
  • [tex] b [/tex] is the y-intercept, the value of y when x = 0.

For Farmer Pisquet:

  • The initial number of gespils is 94, so the y-intercept [tex] b [/tex] is 94.
  • Every hour, he explodes 3 gespils, so the slope [tex] m [/tex] is -3 (because the number of gespils decreases by 3 each hour).

Therefore, the equation representing Farmer Pisquet's gespils is:

[tex] \Large\boxed{\boxed{y = -3x + 94 }}[/tex]

For Farmer Elentire:

  • The initial number of gespils is 67, so the y-intercept [tex] b [/tex] is 67.
  • Every hour, she buys 6 gespils, so the slope [tex] m [/tex] is 6 (because the number of gespils increases by 6 each hour).

Therefore, the equation representing Farmer Elentire's gespils is:

[tex]\Large\boxed{\boxed{ y = 6x + 67}} [/tex]

These equations model the number of gespils for each farmer as hours increase.

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